L’intelligence artificielle :Tutoriel, ses qualifications et comment bénéficier de ses capacités

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   ChatGPT aldhaka’ al’iistinaeiu muahalatih waturuq ‘iistiemalih lil’iistifadat min qudurat ‘iijmaliana hu masdar maftuh majaanan lileumum mahdud almardudiat wamasdar bialmuqabil alshahrii jida mutatawir wahu qadir eali ‘iintaj majmueat wasieat min almuhtawaa almufid lilfardi, sawa’ lilaistikhdam alshakhsii ‘aw almihnii ‘aw altaelimii ‘aw al’iibdaeii kayfiat alwusul ‘iilaa hadhih al’adawat waistikhdamiha alnuskhat almajaania chat.openai.com alnuskhat almadfuea ChatGPT Plus – hawalay 20 dwlaran amrykyan shhryan alwusul ‘iilaa GPT-4o (Omni): ‘asraeu, wa’aqwaa, wamutaeadid alwasayit – nas, surati, sawtin, w fidyu kitabat alrasayil al’iidariati, altahfiziati, shakawaa, alsayr aldhaatiat wakhitabat altaghtia altahdir lilmuqabalat almusaeadat fi altakhtit lilsafari, alfaealiaati, al’ahdaf nasayih hayatiat li’iidarat alwaqti, altanzimu, altawasulu, kitabat rasayil albarid al’iilikturunii, altaqarira, alkhitabat ‘iinsha’ aleurud altaqdimia talkhis watahlil almustanadat daem ‘iinsha’ almasharie -khutat al’aemali, khutat altaswiq ——- EXEMPLE: QUESTION ET REPONSE comment resoudre equation de second degre ChatGPT said: Pour resoudre une equation de second degre (ou equation quadratique), on utilise la formule generale basee sur le discriminant D. Voici comment faire etape par etape : 1. Forme generale Une equation de second degre s’ecrit : ax2+bx+c=0 ax2+bx+c=0 avec a≠0a=0 2. Calcul du discriminant D=b2-4ac D=b2-4ac 3. Etude des cas Si D>0D>0 : 2 solutions reelles distinctes x1=-b-D2a,x2=-b+D2a x1​=2a-b-D ​​,x2​=2a-b+D Si D=0D=0 : 1 solution reelle double x=-b2a x=2a-b​ Si D<0D<0 : Pas de solution reelle (solutions complexes) x1=-b-i|D|2a,x2=-b+i|D|2a x1​=2a-b-i|D| ​​,x2​=2a-b+i|D| 4. Exemple Resolvons 2x2-4x-6=02x2-4x-6=0 a=2a=2, b=-4b=-4, c=-6c=-6 D=(-4)2-4*2*(-6)=16+48=64D=(-4)2-4*2*(-6)=16+48=64 64=864 ​=8 Donc : x1=-(-4)-82*2=4-84=-1 x1​=2*2-(-4)-8​=44-8​=-1 x2=-(-4)+82*2=4+84=3 x2​=2*2-(-4)+8​=44+8​=3 Solutions : x=-1x=-1 et x=3x=3 Si tu veux, donne-moi une equation et je peux la resoudre pour toi ! ----------------------------- barmajat wa'atmitat almahami alnusus albarmajia sharah wadih li'ayi madat -aleulumu, alqanunu, alfalsafatu, altahdir liliamtihanat -'asyilat akhtiar min mutaeadidi, mulakhasatin, 'awraq maelumat altarjamat wa'iieadat alsiyagha dawrat watamarin mukhasasa kitabat alqasayid wal'aghani walqisas alqasira 'iinsha' suar mulldt bialdhaka' alaistinaeii-ebar al'awsaf QUESTION REPONSE: CREER MOI UNE IMGE de JEUNE FILLE BERBERE ROULANT SUR BICYCLETTE A SAN FRANSISCO -USA almusaeadat fi tahrir alfidyu, warasm alqisas almusawarati, watasmim al'aleab nusus al'aflamu, wanusus almasrahiaat alqudrat ealaa 'iinsha' alsuwar watahririha -mithaliat lilrusum albayaniati, walmafahimi, wal'afkar al'iibdaeia qira'at watafsir mustanadat PDF, waljadawila, walrusum albayaniati. tahsin alqudrat ealaa altafkir almantiqi, walbarmajati, walkitabati. alwusul min mutasafih -kumbuyutar, hatifi- eabr chat.openai.com tatbiq ChatGPT liljawal -iOS / Android- almusaeadat fi haykalat masharie 'aw khutat taswiq mantuj mae maelumat altawzie jughrafian wamutatalibat almujtamae alsiyasiat jywbulitik bsm allah alrahman alrahimialsiraeat altahalil alwasayil walqudurat ladaya alshueub tahlil taqdim siaqat wa'ahdaf wanasayih QUESTION REPONSE
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   ChatGPT Artificial Intelligence: Its Qualities and How to Use It to Benefit from Its Capabilities
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   ------

   EXEMPLEMENT: QUESTION ET REPONSE

   Comment resulting from the second-degree equation
   ChatGPT said:
   For a second-degree equalization (or quadratic equalization), on using the general formula basic on the discriminant Δ. Please comment below in the following section:
   1. General form
   One second degree reading method:
   ax2+bx+c=0
   ax2+bx+c=0
   avec a≠0a=0
   2. Calculation of discrimination
   Δ=b2−4ac
   Δ=b2−4ac
   3. Design of the case
   Si Δ>0Δ>0: 2 distinct solutions
   x1=−b−Δ2a,x2=−b+Δ2a
   x1​=2a−b−Δ
   ​​,x2​=2a−b+Δ
   Si Δ=0Δ=0: 1 double solution
   x=−b2a
   x=2a−b​
   Si Δ<0Δ<0: Next solution (solutions complexes)
   x1=−b−i∣Δ∣2a,x2=−b+i∣Δ∣2a
   x1​=2a−b−i∣Δ∣
   ​​,x2​=2a−b+i∣Δ∣
   4. Example
   Résolvons 2x2−4x−6=02x2−4x−6=0
   a=2a=2, b=−4b=−4, c=−6c=−6
   Δ=(−4)2−4×2×(−6)=16+48=64Δ=(−4)2−4×2×(−6)=16+48=64
   64=864
   ​=8
   Donc :
   x1=−(−4)−82×2=4−84=−1
   x1​=2×2−(−4)−8​=44−8​=−1
   x2=−(−4)+82×2=4+84=3
   x2​=2×2−(−4)+8​=44+8​=3
   Solutions: x=−1x=−1 and x=3x=3
   If you have, don't have an equalization and the price is enough for me!

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   ChatGPT Künstliche Intelligenz: Ihre Vorteile und wie Sie sie optimal nutzen
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   ——

   BEISPIEL: FRAGE UND ANTWORT

   Kommentar zur Gleichung zweiten Grades
   ChatGPT sagte:
   Für eine Gleichung zweiten Grades (oder quadratische Gleichung) wird die allgemeine Formel für die Diskriminante Δ verwendet. Bitte kommentieren Sie den folgenden Abschnitt:
   1. Allgemeine Form
   Lesemethode zweiter Ordnung:
   ax2+bx+c=0
   ax2+bx+c=0
   avec a≠0a=0
   2. Berechnung der Diskrimination
   Δ=b2−4ac
   Δ=b2−4ac
   3. Fallgestaltung
   Si Δ>0Δ>0: 2 verschiedene Lösungen
   x1=−b−Δ2a,x2=−b+Δ2a
   x1​=2a−b−Δ
   ​​,x2​=2a−b+Δ
   Si Δ=0Δ=0: 1 doppelte Lösung
   x=−b2a
   x=2a−b​
   Si Δ<0Δ<0: Nächste Lösung (Lösungen Komplexe)
   x1=−b−i∣Δ∣2a,x2=−b+i∣Δ∣2a
   x1​=2a−b−i∣Δ∣
   ​​,x2​=2a−b+i∣Δ∣
   4. Beispiel
   Lösungsgleichungen 2x2−4x−6=02x2−4x−6=0
   a=2a=2, b=−4b=−4, c=−6c=−6
   Δ=(−4)2−4×2×(−6)=16+48=64Δ=(−4)2−4×2×(−6)=16+48=64
   64=864
   ​=8
   Daher:
   x1=−(−4)−82×2=4−84=−1
   x1​=2×2−(−4)−8​=44−8​=−1
   x2=−(−4)+82×2=4+84=3
   x2​=2×2−(−4)+8​=44+8​=3
   Lösungen: x=−1x=−1 und x=3x=3
   Wenn Sie Habe, habe keinen Ausgleich und der Preis reicht mir!

   ----------------------------

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   ——-

   МИСАЛ: САВОЛ ВА ҶАВОБ

   шарҳ resoudre муодилаи дараҷаи дуюм
   ChatGPT гуфт:
   Барои ҳалли муодилаи дараҷаи дуюм (ё муодилаи квадратӣ) мо формулаи умумиро дар асоси дискриминант Δ истифода мебарем. Шарҳи овозӣ faire étape par étape:
   1. Шакли умумӣ
   Муодилаи дараҷаи дуюм навишта мешавад:
   ax2+bx+c=0
   ax2+bx+c=0
   бо a≠0a=0
   2. Calcul du discriminant
   Δ=b2−4ac
   Δ=b2−4ac
   3. Etude des cas
   Si Δ>0Δ>0 : 2 ҳалли воқеии мушаххас
   x1=−b−Δ2a,x2=−b+Δ2a
   x1=2a−b−Δ
   ,x2=2a−b+Δ
   Si Δ=0Δ=0 : 1 ҳалли воқеии дукарата
   x=−b2a
   x=2a−b
   Si Δ<0Δ<0 : Pas de solution réelle (комплексҳои ҳалли)
   x1=−b−i∣Δ∣2a,x2=−b+i∣Δ∣2a
   x1=2a−b−i∣Δ∣
   ​,x2=2a−b+i∣Δ∣
   4. Мисол
   Ҳалли 2x2−4x−6=02x2−4x−6=0
   a=2a=2, b=−4b=−4, c=−6c=−6
   Δ=(−4)2−4×2×(−6)=16+48=64Δ=(−4)2−4×2×(−6)=16+48=64
   64=864
   = 8
   Пас:
   x1=−(−4)−82×2=4−84=−1
   x1=2×2−(−4)−8=44−8=−1
   x2=−(−4)+82×2=4+84=3
   x2=2×2−(−4)+8=44+8=3
   Ҳалли: x=−1x=−1 et x=3x=3
   Агар хоҳед, ба ман як муодила диҳед ва ман онро барои шумо ҳал карда метавонам!

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